Optimal. Leaf size=143 \[ -\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}+\frac{\sqrt{c+d x^2} \left (a d (8 b c-a d)+8 b^2 c^2\right )}{8 c^2}-\frac{\left (a d (8 b c-a d)+8 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x^2}}{\sqrt{c}}\right )}{8 c^{3/2}}-\frac{a \left (c+d x^2\right )^{3/2} (8 b c-a d)}{8 c^2 x^2} \]
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Rubi [A] time = 0.159906, antiderivative size = 140, normalized size of antiderivative = 0.98, number of steps used = 6, number of rules used = 6, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {446, 89, 78, 50, 63, 208} \[ -\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}+\frac{1}{8} \sqrt{c+d x^2} \left (\frac{a d (8 b c-a d)}{c^2}+8 b^2\right )-\frac{\left (a d (8 b c-a d)+8 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x^2}}{\sqrt{c}}\right )}{8 c^{3/2}}-\frac{a \left (c+d x^2\right )^{3/2} (8 b c-a d)}{8 c^2 x^2} \]
Antiderivative was successfully verified.
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Rule 446
Rule 89
Rule 78
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\left (a+b x^2\right )^2 \sqrt{c+d x^2}}{x^5} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{(a+b x)^2 \sqrt{c+d x}}{x^3} \, dx,x,x^2\right )\\ &=-\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}+\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{1}{2} a (8 b c-a d)+2 b^2 c x\right ) \sqrt{c+d x}}{x^2} \, dx,x,x^2\right )}{4 c}\\ &=-\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}-\frac{a (8 b c-a d) \left (c+d x^2\right )^{3/2}}{8 c^2 x^2}+\frac{1}{16} \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{c+d x}}{x} \, dx,x,x^2\right )\\ &=\frac{1}{8} \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right ) \sqrt{c+d x^2}-\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}-\frac{a (8 b c-a d) \left (c+d x^2\right )^{3/2}}{8 c^2 x^2}+\frac{1}{16} \left (c \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{c+d x}} \, dx,x,x^2\right )\\ &=\frac{1}{8} \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right ) \sqrt{c+d x^2}-\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}-\frac{a (8 b c-a d) \left (c+d x^2\right )^{3/2}}{8 c^2 x^2}+\frac{\left (c \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{c}{d}+\frac{x^2}{d}} \, dx,x,\sqrt{c+d x^2}\right )}{8 d}\\ &=\frac{1}{8} \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right ) \sqrt{c+d x^2}-\frac{a^2 \left (c+d x^2\right )^{3/2}}{4 c x^4}-\frac{a (8 b c-a d) \left (c+d x^2\right )^{3/2}}{8 c^2 x^2}-\frac{1}{8} \sqrt{c} \left (8 b^2+\frac{a d (8 b c-a d)}{c^2}\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x^2}}{\sqrt{c}}\right )\\ \end{align*}
Mathematica [A] time = 0.074725, size = 104, normalized size = 0.73 \[ \frac{\sqrt{c+d x^2} \left (-a^2 \left (2 c+d x^2\right )-8 a b c x^2+8 b^2 c x^4\right )}{8 c x^4}-\frac{\left (-a^2 d^2+8 a b c d+8 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d x^2}}{\sqrt{c}}\right )}{8 c^{3/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 207, normalized size = 1.5 \begin{align*} -\sqrt{c}\ln \left ({\frac{1}{x} \left ( 2\,c+2\,\sqrt{c}\sqrt{d{x}^{2}+c} \right ) } \right ){b}^{2}+\sqrt{d{x}^{2}+c}{b}^{2}-{\frac{{a}^{2}}{4\,c{x}^{4}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}+{\frac{{a}^{2}d}{8\,{c}^{2}{x}^{2}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}+{\frac{{a}^{2}{d}^{2}}{8}\ln \left ({\frac{1}{x} \left ( 2\,c+2\,\sqrt{c}\sqrt{d{x}^{2}+c} \right ) } \right ){c}^{-{\frac{3}{2}}}}-{\frac{{a}^{2}{d}^{2}}{8\,{c}^{2}}\sqrt{d{x}^{2}+c}}-{\frac{ab}{c{x}^{2}} \left ( d{x}^{2}+c \right ) ^{{\frac{3}{2}}}}-{abd\ln \left ({\frac{1}{x} \left ( 2\,c+2\,\sqrt{c}\sqrt{d{x}^{2}+c} \right ) } \right ){\frac{1}{\sqrt{c}}}}+{\frac{abd}{c}\sqrt{d{x}^{2}+c}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.68348, size = 497, normalized size = 3.48 \begin{align*} \left [-\frac{{\left (8 \, b^{2} c^{2} + 8 \, a b c d - a^{2} d^{2}\right )} \sqrt{c} x^{4} \log \left (-\frac{d x^{2} + 2 \, \sqrt{d x^{2} + c} \sqrt{c} + 2 \, c}{x^{2}}\right ) - 2 \,{\left (8 \, b^{2} c^{2} x^{4} - 2 \, a^{2} c^{2} -{\left (8 \, a b c^{2} + a^{2} c d\right )} x^{2}\right )} \sqrt{d x^{2} + c}}{16 \, c^{2} x^{4}}, \frac{{\left (8 \, b^{2} c^{2} + 8 \, a b c d - a^{2} d^{2}\right )} \sqrt{-c} x^{4} \arctan \left (\frac{\sqrt{-c}}{\sqrt{d x^{2} + c}}\right ) +{\left (8 \, b^{2} c^{2} x^{4} - 2 \, a^{2} c^{2} -{\left (8 \, a b c^{2} + a^{2} c d\right )} x^{2}\right )} \sqrt{d x^{2} + c}}{8 \, c^{2} x^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 73.1166, size = 219, normalized size = 1.53 \begin{align*} - \frac{a^{2} c}{4 \sqrt{d} x^{5} \sqrt{\frac{c}{d x^{2}} + 1}} - \frac{3 a^{2} \sqrt{d}}{8 x^{3} \sqrt{\frac{c}{d x^{2}} + 1}} - \frac{a^{2} d^{\frac{3}{2}}}{8 c x \sqrt{\frac{c}{d x^{2}} + 1}} + \frac{a^{2} d^{2} \operatorname{asinh}{\left (\frac{\sqrt{c}}{\sqrt{d} x} \right )}}{8 c^{\frac{3}{2}}} - \frac{a b \sqrt{d} \sqrt{\frac{c}{d x^{2}} + 1}}{x} - \frac{a b d \operatorname{asinh}{\left (\frac{\sqrt{c}}{\sqrt{d} x} \right )}}{\sqrt{c}} - b^{2} \sqrt{c} \operatorname{asinh}{\left (\frac{\sqrt{c}}{\sqrt{d} x} \right )} + \frac{b^{2} c}{\sqrt{d} x \sqrt{\frac{c}{d x^{2}} + 1}} + \frac{b^{2} \sqrt{d} x}{\sqrt{\frac{c}{d x^{2}} + 1}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.11195, size = 207, normalized size = 1.45 \begin{align*} \frac{8 \, \sqrt{d x^{2} + c} b^{2} d + \frac{{\left (8 \, b^{2} c^{2} d + 8 \, a b c d^{2} - a^{2} d^{3}\right )} \arctan \left (\frac{\sqrt{d x^{2} + c}}{\sqrt{-c}}\right )}{\sqrt{-c} c} - \frac{8 \,{\left (d x^{2} + c\right )}^{\frac{3}{2}} a b c d^{2} - 8 \, \sqrt{d x^{2} + c} a b c^{2} d^{2} +{\left (d x^{2} + c\right )}^{\frac{3}{2}} a^{2} d^{3} + \sqrt{d x^{2} + c} a^{2} c d^{3}}{c d^{2} x^{4}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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